Question

$3 {x}^{2} + \sqrt{3}x - 2 = 0$
find the nature of roots
(quadratric equations)​

Answer 1

Answer:

sum of roots is 9

Step-by-step explanation:

mar as bsuu

Answer 2

SOLUTION:-

$\bf\underline{\underline{\red{Question:-}}}$

⠀⠀⠀⠀⠀• Find the nature of the roots of the ⠀⠀⠀⠀⠀Quadratic equation 3x²+ √3x-2=0

$\bf\underline{\underline{\blue{Answer:-}}}$

⠀⠀⠀⠀⠀• The roots are real and unequal

$\bf\underline{\underline{\red{Given:-}}}$

⠀⠀⠀⠀⠀• Quadratic equation 3x²+√3x-2=0

$\bf\underline{\underline{\blue{To\: Find:-}}}$

⠀⠀⠀⠀⠀• Nature of the roots

$\bf\underline{\underline{\red{Explanation:-}}}$

The Given equation ➫ 3x²+√3x-2=0

This is of the form ax²+bx+c=0

$\bf\underline{\underline{\green{Where:-}}}$

a ➫ 3

b ➫ √3

c ➫ -2

We know that,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$\boxed{D= b²-4ac}$

putting values,

➺ D= b²-4ac

➫ (√3)²-4×3×(-2)

➫ 3-(-24)

➫ 3+24

➫ 27

27>0

$\bf\underline{\underline{\</strong><strong>green</strong><strong>{</strong><strong>Hence</strong><strong>:-}}}$

⠀⠀⠀⠀⠀• The Given equation has Real and unequal ⠀⠀⠀⠀⠀roots.

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