Question

$3(x - 4) {}^{2} - 5(x - 4) = 12$
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Answer 1

$\huge\mathtt{{\color{yellow}{AnS}}{\color{red}{wEr!}}}$

$\small{ }$

$\large\bold\color{navy}{Given:}$

$\large\bold{3(x-4)^2-5(x-4)=12}$

$\large\bold{3×(x^2-8x+16)-5x-20=12}$

$\large\bold{3x^2-24x+48-5x-20=12}$

$\large\bold{3x^2-29x+28=12}$

$\large\bold{3x^2-29x+28-12=0}$

$\large\bold{{\underline{\underline{3x^2-29x+16=0}}}}$

$\small{ }$

Sorry, couldn't complete the answer as you haven't mentioned what should be done with the given expression...

$\huge\bold\color{navy}{Hope~this~helps!}$