Question

${3}^{x + 4} - 6 \times {3}^{x + 1} \div {3}^{x + 2}$
please quickly answer the question
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Answer 1

Step-by-step explanation:

${3}^{x + 4} - 6 \times {3}^{x + 1} \div {3}^{x + 2}\\\\</p><p>={3}^{x + 4} - 2\times 3\times {3}^{x + 1} \div {3}^{x + 2}\\\\</p><p>={3}^{x + 4} - 2\times {3}^{x + 1+1} \div {3}^{x + 2}\\\\ ={3}^{x + 4} - 2\times {3}^{x + 2} \div {3}^{x + 2}\\</p><p>\\</p><p>= {3}^{x + 4} - 2\times\frac {{3}^{x + 2}}{{3}^{x + 2}}\\\\</p><p>= {3}^{x + 4} - 2\\</p><p>$