Question

$3 {x} + 64 = {2}^{6} + (\sqrt{3} ) ^{8}$
find the value of x
​

Answer 1

Answer:

The value of x is 27.

Step-by-step explanation:

The expression is:

$3x+64=2^{6}+(\sqrt{3})^{8}$

Solve for x as follows:

$3x+64=2^{6}+(\sqrt{3})^{8}\\3x+64=64+[3^{\frac{1}{2}{\times8}}]\\3x=3^{4}\\x=\frac{3^{4}}{3}\\x=3^{3}\\=27$

Thus, the value of x is 27.