Solve the following quadratic equation
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Answer:
(x−1)(x+1)=(2x−5)(3x−7)
Let us simplify the given equation,
By cross multiplying
(x−1)(3x−7)=(2x−5)(x+1)
3x
2
−7x−3x+7=2x
2
+2x−5x−5
3x
2
−10x+7−2x
2
+3x+5=0
x
2
−7x+12=0
By factorizing, we get
x
2
−4x−3x+12=0
x(x−4)−3(x−4)=0
(x−4)(x−3)=0
So,
(x−4)=0 or (x−3)=0
x=4 or x=3
∴ Value of x=4,3
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