Question

$300m \: + \: 20n = \frac{11}{20} \\ 26m \: + \: 24n = \frac{28}{50}$
solve these eq. using elimination method.

Answer 1

Step-by-step explanation:

$300m + 20n = \frac{11}{20}...(1)$

$26m + 24n = \frac{28}{50}...(2)$

Multiply (1) by 6 and (2) by 5. Then subtract (2) from (1) we get

$6(300m + 20n) - 5(26m + 24n) =$

$\frac{5 \times 11}{20} - \frac{28 \times 6}{50} = > 1800m + 120n -$

$130m - 120n = 2.75 - 3.36 = >$

$1670m = - 0.61 = > m = \frac{ - 0.61}{1670}$

Substitute it in equation (1) then find n also. Hope it helps you.