Question

$32x ^{2} + 160x - 192$
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Answer 1

Step-by-step explanation:

$32 {x}^{2} + 160x - 192$

Factor out 32 from the expression

$32( {x}^{2} + 5x - 6)$

Write 5x as a difference

$32( {x}^{2} + 6x - x - 6)$

Factor out x from the expression

$32(x \times (x + 6) - x - 6$

$32(x \times (x + 6) - (x + 6))$

Factor out x + 6 from the expression

$32(x + 6) \times (x - 1)$

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