Question

$36 {t}^{ - 3} \div {6}^{ - 3} \times} {t}^{ - 5}$
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Answer 1

Step-by-step explanation:

$36 {t}^{ - 3} \div {6}^{ - 3} \times {t}^{ - 5} \\ \\ \\ = 36t^{ - 3} \times \frac{1}{ {6}^{3} } \times {t}^{ - 5} \\ \\ = {t}^{ - 3 - 5} \times \frac{36}{6 \times 6 \times 6} \\ \\ = {t}^{ - 8} \times \frac{1}{6} \\ \\ \\ = \frac{1}{6 {t}^{8} }$

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