Question

$36x {}^{2} + 96xy + 64y {}^{2}$
factorise this

Answer 1

given that,

36x^2+96xy+64y^2

=(6x)^2+2*6x*8y+(8y)^2

this is in the form of a^2 +2ab+b^2

so a^2+2ab+b^2=(a+b)^2

=(6x+8y)^2

=(6x+8y)(6x+8y).

:-)hope it helps u.

Answer 2

36x {}^{2} + 96xy + 64y {}^{2}
= 36x {}^{2} + 48xy + 48xy + 64y {}^{2}
= 6x (6x + 8y) + 8y (6x + 8y)
= (6x+8y)+(6x+8y)

i.e 36x {}^{2} = 64y {}^{2}

divide each side by 36

x2 = 1.777777778y2

Simplifying x2 = 1.777777778y2

Take the square root of each side:
x= {-1.333333333y, 1.333333333y}