Question

$37x + 41y = 70$
$41x + 37y = 86$
​

Answer 1

linear equations in 2 variables:

37x+ 41y= 70.....(1)

+ 41x+37y=86......(2)

78x+ 78y= 156

therefore,

78x+78y= 156

x+ y= 2......(3)

also,

37x+ 41y= 70

- 41x-37y= -86

-4x+ 4y= - 16

x- y= 4....(4)

now, adding (3) and (4)

x+y= 2

+x-y=4

2x= 6

x= 6/2= 3

substituting the value of x in (3)

x+y= 2

3+y= 2

y = 2-3

y= -1

therefore,

x, y= 3,-1

hope this helps mate! ❤✌☺

Answer 2

Solution:-

Given Equations:-

37x + 41y = 70

37x + 41y = 7041x + 37y = 86.

Explanation:-

In Questions like this, we usually First Add both the Equations and Then Subtract one Equation from the other.

In Questions like this, we usually First Add both the Equations and Then Subtract one Equation from the other.By the Two Resultant Equation, we Solve the Question Further.

Adding both the Equation.

37x + 41y = 70

41x + 37y = 86.

______________

78x + 78y = 156 __________(1).

Subtracting Both the Equation.

37x + 41y = 70

41x + 37y = 86.

_____________

(-4x) + 4y = (- 16)

=) 4y = 4x - 16

=) y = x - 4__________(2)

Putting ( y = x-4) in Equation (1). we get,

=) 78x + 78( x-4) = 156

=) 78x + 78x - 312 = 156

=) 156x = 156 + 312

=) 156x = 468

=) x = 3.

Putting ( x=3) in Eq (2).

=) y = 3 - 4

=) y = -1

Hence Solved!