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Answered by
4
Solution:
(3a-1)(3a-1)-6a+2
=(3a-1)(3a-1)-2(3a-1)
= (3a-1)[3a-1-2]
=(3a-1)[3a-3]
= (3a-1)[3(a-1)]
= 3(a-1)(3a-1)
Therefore,
(3a-1)(3a-1)-6a+2 =3(a-1)(3a-1)
•••
supershiva:
have you join any coaching of maths and in which class are yoi
Answered by
1
(3a-1)(3a-1)-6a+2
= 9a^2 -6a+1 - 6a + 2
= 9a^2 - 12a +3
= 9a^2 - 9a - 3a + 3
= 9a(a-1) -3(a-1)
= (9a -3)(a-1)
= 3(3a-1)(a-1)
wrong
can I know what is wrong in it
answer is 3 (3a-1)(a-1)
Now see is it right or wrong .it is just taking 3 common
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