Question

$(3a - 2b) {}^{2}$
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Answer 1

${(3a - 2b)}^{2}$

$= {(3a)}^{2} + {(2b)}^{2} - 2 \times 3a \times 2b$

$= 9 {a}^{2} + 4 {b}^{2} - 12ab$

Answer 2

Solution:

$(3a - 2b) {}^{2}$

we know that,

$\boxed{(a-b)^{2}=a^2-2ab+b^2   }$ 

so,

• $(3a - 2b) {}^{2}$
• $\tt{(3a)^2-2×3a×2b+(2b)^{2}   }$ 
• $\bold{9a^{2}-12ab+4b^{2}   }$