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Q..(3a+2b)^3-(3a-2b)^3
Let 3a be x and 2b be y
Then
(x+y)^3-(x-y)^3
=x^3+y^3+3×xy(x+y)-{x^3-y^3-3×xy(x-y)}
=x^3+y^3+3x^2y+3xy^2-{x^3-y^3-3x^2y+3xy^2}
=x^3+y^3+3x^2y+3xy^2-x^3+y^3+3x^2y-3xy^2
=y^3+y^3+3x^2y+3x^2y
=2y^3+6x^2y
Put the value of x and y
=2×(2b)^3+6×(3a)^2×2b
=2×8b^3+6×9a^2×2b
=16b^3+108a^2b
Ok
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