Question

$(3k + 1)x2 + 2(k + 1)x + k$
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Answer 1

Answer:

3k+1)x

2

−2(k+1)x+1=0

when D=0,then the equation real equal roots.

D=b

2

−4ac=0

⇒(−2(k+1))

2

−4(3k+1)(1)=0

⇒4(k+1)

2

−4(3k+1)=0

⇒k

2

+1+2k−3k−1=0

⇒k

2

−k=0

⇒k(k−1)=0

so k=0 or k=1