Question

$3p {}^{2} - 8 \sqrt{} 3p + 16$
answer this question please send full solving

Answer 1

compairing with quadratic equation ax^2+bx+c=0
we get a=3
B=-8√3
c=16
$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{2a} \\ \frac{ - ( - 8 \sqrt{3}) + - \sqrt{(8 \sqrt{3} ) {}^{2} - 4 \times 3 \times 16} }{2 \times 3} \\ \frac{8 \sqrt{3} + - \sqrt{192 - 192} }{6} \\ \frac{8 \sqrt{3} }{6} \\ \frac{4 \sqrt{3} }{3}$
this is the solution to the answer.
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