Question

$3x {}^{2} + 10x + 3$
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Answer 1

Solve this by the quadratic formula.

Quadratic formula = $\tt{\frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}$

Here, for this question the values of a, b and c are:

a = 3

b = 10

c = 3

Solve:

x = $\tt{\frac{-10 \pm \sqrt{10^{2} - 4(3)(3)}}{2(3)}}$

x = $\tt{\frac{-10 \pm \sqrt{100-36}}{6}}$

x = $\tt{\frac{-10 \pm \sqrt{64}}{6}}$

x = -3, -1/3

Answer 2

Answer:- 3x^2+10x+3=0

3x^2+9x+1x+3=0

3x(x+3)+1(x+3)=0

(x+3)(3x+1)=0

x= -3 or x= -1/3

Hope it helps!

Plz... Mark it as BRAINIEST.