Question

$3x {}^{2} + 13x + 12$
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Answer 1

Step-by-step explanation:

$3 x^{2} + 13x + 12 = 0 \\ 3x {}^{2} + 9x + 4x + 12 = 0 \\ 3x(x + 3) + 4(x + 3) = 0 \\ (3x + 4)(x + 3) = 0 \\ 3x + 4 = 0 \\ 3x = - 4 \\ x = \frac{ - 4}{3} \\ x = - 3$

Answer 2

Answer:

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