Math, asked by roshniii62, 10 months ago


3x^{2}  + 2 \sqrt{5 }  - 5 = 0

Answers

Answered by Anonymous
5

Answer:

x \:  =  \:  -  \:  \sqrt{5}  \:  \: or \:  \:x \:  =  \:  \dfrac{ \sqrt{5} }{3}

Step-by-step explanation:

3 {x}^{2}   \: + \:  2 \sqrt{5} x \:  -  \sqrt{5}  \:  =  \: 0 \\  \\ 3 {x}^{2}  \:  +  \: 3 \sqrt{5} x \:  -  \:  \sqrt{5} x \:  -  \: 5 \:  =  \: 0 \\  \\ 3x \: ( \: x \:  +  \:  \sqrt{5}  \: ) \:  -  \:  \sqrt{5}  \: ( \: x \:  +  \:  \sqrt{5}  \: ) \:  =  \: 0 \\  \\ x \:  +  \:  \sqrt{5}  \:  =  \: 0 \:  \:  \: or \:  \:  \: 3x \:  -  \:  \sqrt{5}  \:  =  \: 0 \\  \\ x \:  =  \:  -  \:  \sqrt{5}  \:  \: or \:  \: 3x \:  =  \:  \sqrt{5}  \\  \\ x \:  =  \:  -  \:  \sqrt{5}  \:  \: or \:  \:x \:  =  \:  \frac{ \sqrt{5} }{3}

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