Question

$3x {} {}^{ 2} - 2 \sqrt{6} x + 2 = 0$
answer step by step




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Answer 1

Step-by-step explanation:

3x² - 2√6x + 2 = 0

We will factorise

Using splitting midterm theorem

3x² - √6x - √6x + 2 = 0

3x² - √2 × 3x - √ 2 × 3x + 2 = 0

3x² - ( √2 ) ( √3 )x - (√2)(√3)x + 2 = 0

3x² ( √3x - √2 ) - √2 ( √3x - √2 ) = 0

( √ 3x - √2 ) ( √3x - √ 2 ) = 0

√ 3x - √2 = 0

√3x = √2

x = √2 / √3

√3x - √2 = 0

$\sqrt{ \frac{2}{3} }$

√3x = √2

x = √2 / √ 3

Hence x =

$\sqrt{ \frac{2}{3} }$

$hope \: it \: helps \: you$

Answer 2

Step-by-step explanation:

3x² - 2√6x + 2 = 0

We will factorise

Using splitting midterm theorem

3x² - √6x - √6x + 2 = 0

3x² - √2 × 3x - √ 2 × 3x + 2 = 0

3x² - ( √2 ) ( √3 )x - (√2)(√3)x + 2 = 0

3x² ( √3x - √2 ) - √2 ( √3x - √2 ) = 0

( √ 3x - √2 ) ( √3x - √ 2 ) = 0

√ 3x - √2 = 0

√3x = √2

x = √2 / √3

√3x - √2 = 0

\sqrt{ \frac{2}{3} }

3

2

√3x = √2

x = √2 / √ 3

Hence x =

\sqrt{ \frac{2}{3} }

3

2