Question

$3x ^{2} - 2 \sqrt{6x } + 2$
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Answer 1

First of all what is the equation equal to ?
If it is equal to zero then follow these steps :



Use quadratic formula , that if ax^2 + bx + c =0

Then x = ((-b)±√(b²-4ac))/(2a)

If you compare the question and this equation , then you can write

a= 3
b= -2 √6
c= 2

Therefore now x = ((-b)±√(b²-4ac))/(2a)

= (2√6 ±( √(-2 √6)^2 - 4(3)(2) ) ) / (2)(3)

Simply this equation ....


x = (2√6 ±( √(24- 24) ) / 6

x= (2√6 ±( √0 ) ) / 6


x=2√6 / 6

x= 2/√6



Hope you understood it , if yes then please leave a thank , and don’t forget to mark this answer as brainiest answer if you understood

Answer 2

X=root2 by root3 is the answer so bye have a great day bye bye