Question

$3x^{2} -4\sqrt{3} x+4=0$
find roots

Answer 1

Answer:

$x = \frac{2 }{ \sqrt{3} } \: \: \: \: \: \: \frac{ 2}{ \sqrt{3} }$

Step-by-step explanation:

$3x^{2} -4\sqrt{3} x+4=0 \\ 3 {x}^{2} - 2 \sqrt{3}x - 2 \sqrt{3} x + 4 = 0 \\ \sqrt{3} x( \sqrt{3} x - 2) - 2( \sqrt{3} x - 2) = 0 \\ ( \sqrt{3} x - 2)( \sqrt{ 3} x - 2) = 0 \\ \sqrt{3} x - 2 = 0 \\ either \: \: \: \sqrt{3} x = 2 \: \: \: \: \: \: \: \: or \: \sqrt{3}x = 2 \\ x = \frac{2}{ \sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{2}{ \sqrt{3} }$