Question

$3x {}^{2} - 4 \sqrt{3x } + 4 = 0$
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Answer 1

Explanation:

3x² - 4√3x + 4 = 0

=> 3x² - 2√3x - 2√3x + 4 = 0

=> √3x * √3x - 2√3x - 2√3x + 4 = 0

=> √3x(√3x - 2) - 2(√3x - 2) =0

=> (√3x - 2)(√3x - 2) = 0

=> √3x - 2 = 0

therefore x = 2/√3