Question

$(3x ^{2} + 4x)(y ^{2} + 8x + 1)$
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Answer 1

$\left(3x^2+4x\right)\left(y^2+8x+1\right)$

= $3x^2y^2+3x^2\cdot \:8x+3x^2\cdot \:1+4xy^2+4x\cdot \:8x+4x\cdot \:1$

= $3x^2y^2+3\cdot \:8x^2x+3\cdot \:1\cdot \:x^2+4xy^2+4\cdot \:8xx+4\cdot \:1\cdot \:x$

= $24x^3+3x^2y^2+35x^2+4xy^2+4x$

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