Question

${3x}^{2} - 6x + 2 = 0$
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Answer 1

HERE GIVEN ,

$3 {x}^{2} - 6x + 2 = 0$

a=3 , b=-6 and c=2

Use the formula

$x = \frac{ - b </strong><strong>\</strong><strong>p</strong><strong>m</strong><strong> \sqrt{b^{2} - 4ac } }{2a}$

so put the values

$x = \frac{ - ( - 6) </strong><strong>\</strong><strong>p</strong><strong>m</strong><strong> \sqrt{( -6) {}^{2} - 4(3)(2)} }{2(3)} \\ = > \frac{6 </strong><strong> </strong><strong>\</strong><strong>p</strong><strong>m</strong><strong> \sqrt{36 - 24} }{6} \\ = >\frac{6 </strong><strong>\</strong><strong>p</strong><strong>m</strong><strong> 2 \sqrt{3} }{6}$

x=

$\boxed {\frac{6 + 2 \sqrt{3} }{6} }$

or

x=

$\boxed{ \frac{6 - 2 \sqrt{3} }{6} }$

Answer 2

3x^2-6x+2=0

a=3 b =-6 and c=2

x=-b+-√(b^2-4ac)/2a

×=-(-6)+-√(36-24)/6

=6+-(√12)/6

x= 6+√12/6

and

x=6-√12/6