guys do this by formula method.
lesson name : polynomials
Answers
hi mate,
solution:
3x²-6x+7=0
Solving 3x²-6x+7 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax²+Bx+C = 0 ,
- B ± √ B²-4AC
x = ————————
2A
In our case, A = 3
B = -6
C = 7
Accordingly, B2 - 4AC =
36 - 84 =
-48
Applying the quadratic formula :
6 ± √ -48
x = —————
6
Accordingly,√ -48 =
√ 48 • (-1) =
√ 48 • √ -1 =
± √ 48 • i
√ 48 = √ 2•2•2•2•3 =2•2•√ 3 =
± 4 • √ 3
√ 3 , rounded to 4 decimal digits, is 1.7321
So now we are looking at:
x = ( 6 ± 4 • 1.732 i ) / 6
Two imaginary solutions :
x =(6+√-48)/6=1+2i/3√ 3 = 1.0000+1.1547i
or:
x =(6-√-48)/6=1-2i/3√ 3 = 1.0000-1.1547i
Two solutions were found :
x =(6-√-48)/6=1-2i/3√ 3 = 1.0000-1.1547i
x =(6+√-48)/6=1+2i/3√ 3 = 1.0000+1.1547i
i hope it helps you.