Question

$(3x - 4)(2x ^{2} - 5x + 1) -(2x - 1)(3x ^{2} + 7x - 5)$
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Answer 1

Step-by-step explanation:

(3x-4)(2x^2-5x+1)-(2x-1)(3x^2+7x-5)

=(6x^3-8x^2-15x^2+20x+3x-4)-

(6x^3-3x^2+14x^2-7x-10x+5)

=(6x^3-23x^2+23x-4)-(6x^3+11x^2-17x+5)

=6x^3-23x^2+23x-4-6x^3-11x^2+17x-5

= -34x^2+40x-9

Answer 2

Answer:

$\left(3x-4\right)\left(2x^2-5x+1\right)-\left(2x-1\right)\left(3x^2+7x-5\right)$

$6x^3-23x^2+23x-4-\left(2x-1\right)\left(3x^2+7x-5\right)$

$6x^3-23x^2+23x-4-6x^3-11x^2+17x-5$

$6x^3-6x^3-23x^2-11x^2+23x+17x-4-5$

$-34x^2+40x-9$

$@rohangupta0424$