Sove the equation by substitution method....
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3x+7y=37
5x+6y=39
(3x+7y)-(5x+6y)=37-39
3x+7y-5x-6y)=-2
-2x+y=-2
So in this there are 2 values of both x and y.
1st Values:-
-2x+y=-2
-2(1)+0=-2
-2=-2
Therefore x=1 and y=0.
2nd Values:-
-2x+y=-2
-2(0)+(-2)=-2
0-2=-2
-2=-2
Therefore x=0 and y=-2.
I hope this helps you and please mark me the Brainliast.
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