Question

$3x - \frac{1}{4} = 11 \\ find \: x \: solve \: with \: showing \\the \: steps$
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Answer 1

Step-by-step explanation:

$\qquad\quad\sf{:}\longrightarrow 3x-\dfrac{1}{4}=11$

• Add the left side.

$\qquad\quad\sf{:}\longrightarrow \dfrac{12x-1}{4}=11$

• use cross multiplication method.

$\qquad\quad\sf{:}\longrightarrow 12x-1=44$

$\qquad\quad\sf{:}\longrightarrow 12x=44+1$

$\qquad\quad\sf{:}\longrightarrow 12x=45$

$\qquad\quad\sf{:}\longrightarrow x=\dfrac{45}{12}$

$\qquad\quad\sf{:}\longrightarrow x=3.7$

Answer 2

$\large\underline\blue{\bold{Given\:Question - }}$

$\bf \: Solve \: for \: x : \: 3x - \dfrac{1}{4} = 11$

$\large\underline\purple{\bold{Solution :- }}$

$\rm :\implies\:3x - \dfrac{1}{4} = 11$

$\rm :\implies\:3x = 11 + \dfrac{1}{4}$

$\rm :\implies\:3x = \dfrac{44 + 1}{4}$

$\rm :\implies\:3x = \dfrac{45}{4}$

$\rm :\implies\: \boxed{ \red{ \bf \: x = \dfrac{15}{4} }}$

Verification

$\bigstar \: \bf \: Consider \: LHS$

$\rm :\implies\:3x - \dfrac{1}{4}$

On substituting the value of x, we get

$\rm :\implies\:3 \times \dfrac{15}{4} - \dfrac{1}{4}$

$\rm :\implies\:\dfrac{45}{4} - \dfrac{1}{4}$

$\rm :\implies\:\dfrac{45 - 1}{4}$

$\rm :\implies\:\dfrac{44}{4}$

$\rm :\implies\:11$

$\bf :\implies\: = \: RHS$

$\large{\boxed{\boxed{\bf{Hence, verified}}}}$