Question

$3x + \frac{5}{16x} - 2 = 0$
solve it with explain​

Answer 1

Answer:

$3x + \frac{5}{16x} - 2 = 0 \\ \\ \frac{48 {x}^{2} + 5 - 32x }{16x} = 0 \\ \\ 48 {x}^{2} + 5 - 32x = 0 \\ \\ 48 {x}^{2} - 32x + 5 = 0 \\ \\ in \: this \: equation \: a = 48 \\ b = - 32 \: c = 5 \\ \\ x = \frac{ - b + - \sqrt{ {b}^{2} } - 4ac } {2a} \\ \\ = \frac{ - ( - 32) + - \sqrt{ { - 32}^{2} } - 4 \times 48 \times 5 }{2 \times 48} \\ \\ = \frac{32 + - \sqrt{1024 - 960} }{96} = \frac{32 + - \sqrt{64} }{96} \\ \\ \frac{32 + - 8}{96} \\ \\ x = \frac{32 + 8}{96} or \: \: x = \frac{32 - 8}{96} \\ \\ x = \frac{40}{96} or \: x= \frac{24}{96} \\ x = \frac{5}{12} orx = \frac{1}{4}$

the two elements of the equation is 5/12 or 1/4

Answer 2

Step-by-step explanation:

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