Question

حالا
$3x + y = 1 \\ (2k - 1) x + (k - 1)y = 2k + 1$
​

Answer 1

Answer:

3x+y=1

(2k−1)x+(k−1)y=(2k+1)

For no solution

a

2

a

1

=

b

2

b

1



=

c

2

c

1

Then

2k−1

3

=

k−1

1



=

2k+1

1

⇒3k−3=2k−1⇒k=2

Answer 2

Step-by-step explanation:

3x + y = 1

y = 1-3x

putting the value of y

(2k-1)x + (k-1)y = 2k + 1

2kx - x + (k-1)(1-3 x) =2k +1

2kx -x + k -3kx -1 + 3x = 2k + 1

-kx +2x -k -2