Math, asked by shivakanya654, 8 months ago


3x + y = 1 \:  \: 2x - 11y = 3
ही समीकरणे क्रेमरच्या पद्धतीने सोडवताना Dy ची किमत किती​

Answers

Answered by SumayTode458
3

Step-by-step explanation:

<body bgcolor=black><marquee direction="up"><font color=red>

3x+y=1----------------(1)

2x-11y=3--------------(2)

lets compare eq 1 with eq3

eq2 with eq 4

a1x+b1y=c1-----------(3)

a2x-b2y=c2------------(4)

a1=3, b1=1, c1=1

a2=2, b2=11, c2=3

Dy=|a1. c1| 3×3-2×1=9-2=7

|a2. c2|

<svg height="210" width="500">\ \textless \br /\textgreater \ <polygon points=" 100,10,40,198,190,78,10,78,160,198"\ /textareafor style="till:line stroke purple;stroke-width Still rule:nonzero;" />\textless br. textereater </svg>

<svg width="350" height="350" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="red" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="15"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>Follow me

Similar questions