Question

$3x2 - x - 4$
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Answer 1

Answer:

$3 {x}^{2} - x - 4 \\ = 3 {x}^{2} - (4 - 3)x - 4 \\ = 3 {x}^{2} - 4x + 3x - 4 \\ = x(3x - 4)1(3x - 4) \\ = (3x - 4)(x + 1)$

Hopefully it will be a great to you

Answer 2

$\huge\boxed{\red{Answer}}$

By the method of of prime factorisation .. we can solve this question

Now According to question:-

$\sf 3x{}^{2}-x-4\\ \sf 3x{}^{2}-(4-3)x-4\\ \sf 3x{}^{2}-4x+3x-4\\ \sf x(3x-4)-1(3x-4)\\ \sf (3x-4) (x-1)$

Then find the zero's

$\sf 3x-4=0\\ \sf 3x=4\\ \sf x=\frac{4}{3}\\ \ x-1=0\\ \sf x=1$

Factors :--

$\boxed{\red{(3x-4)(x-1)}}$

Zero's:-

$\boxed{\red{(\frac{4}{3},1)}}$