Math, asked by souradeepmandal66, 1 year ago


3y  {}^{2}  - 20  = 160 - 2y {}^{2}

Answers

Answered by warrior24
1

Answer:

3 {y}^{2}  - 20 = 160 - 2 {y}^{2}

5 {y}^{2}  = 180

 {y}^{2}  =  \frac{180}{5}

 {y}^{2}  = 36

y = 6

Answered by yash12384
0

Answer:

3y^2-20=160-2y^2

3y^2+2y^2=160+20

5y^2=180

y^2=180/5

y^2=36

taking square root

y=6

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