Question

$3y ^{2} - ky + 8 = 0 \: \: y = \frac{3}{2}$​

Answer 1

$\implies \large\tt{ {3y}^{2} – ky + 8 = 0}$

y = 2/3, is the root of given quadratic equation.

So it satisfies the given equation.

∴ 3(2/3)2 – k(2/3)  + 8 = 0

∴ 3(4/9) – 2k/3 + 8 =0

∴ 12/9 – 2k/ 3 + 8 = 0

Multiplying the equation by 9 we get,

12 – 6k + 72 = 0

∴ 6k = 84

∴  k = 84/6

$\implies$

∴ k = 14

Answer 2

Answer:

hey there here's your answer

Answer :-

y = 2/3, is the root of given quadratic equation.

So it satisfies the given equation.

∴ 3(2/3)2 – k(2/3)  + 8 = 0

∴ 3(4/9) – 2k/3 + 8 =0

∴ 12/9 – 2k/ 3 + 8 = 0

Multiplying the equation by 9 we get 0

12 – 6k + 72 = 0

∴ 6k = 84

∴  k = 84/6

\implies⟹

∴ k = 14