Question

$3y2 + x - 4$
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Answer 1

$\color{red} \huge \underline \bold{3 {y}^{2} + y - 4}$

______First step_______{ multiple 3y² and -4 i e first term and last term }

3y²*(-4)=-12y²

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Now

______2nd step_______ Split the middle term i.e 1y in that form so its spliting sum or subt6 be answer of (1y) or multiple of same number be (-12y²)

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LET' S DO.....

Make factors of (-12)

-2*6=12

4*-3=12

If we use 2nd then sum of or subtract of both make the answer (1y)

NOW COME TO UR QUESTION

SOLUTION.

$3 {y}^{2} + y - 4$

3y²+4y-3y-4

y(3y+4)-1(3y+4)=0

(y-1)(3y+4)=0

y-1=0 3y+4=0

y=(1) 3y=(-4)

y=(1) y=-4/3

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HOPE ITS HELPFUL TO ALL ☺️❤️