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Answer:
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Answered by
1
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Solution
verified
Verified by Toppr
The given equation is 49y
2
−16x
2
=784
It can be written as
49y
2
−16x
2
=784
16
y
2
−
49
x
2
=1
4
2
y
2
−
7
2
x
2
=1 ...(1)
On comparing equation (1) with the standard equation of hyperbola
i.e.,
a
2
y
2
−
b
2
x
2
=1
we obtain a=4 and b=7
We know that a
2
+b
2
=c
2
, where c=ae
∴c
2
=16+49=65
⇒c=
65
Therefore, the coordinates of the foci are (0,±
65
)
The coordinates of the vertices are (0,±4)
Eccentricity e=
a
c
=
4
65
Length of latus rectum =
a
2b
2
=
4
2×49
=
2
49
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