Question

$(4 {}^{ - 1} + 8 {}^{ - 1) } \div ( \frac{4}{9} ) {}^{ - 1}$
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Answer 1

Answer:

1/6

Step-by-step explanation:

$\frac{(4^{-1}+ 8^{-1} )}{(\frac{4}{9})^{-1} } \\\\=\frac{\frac{1}{4}+\frac{1}{8} }{\frac{9}{4} }\\\\=\frac{\frac{3}{8} }{\frac{9}{4} } \\\\=\frac{1}{6}$