Question

$( {4}^{ - 1} + 8 {}^{ - 1} ) \times (\frac{4}{9} ) {}^{ - 1}$
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Answer 1

Step-by-step explanation:

1. $( {4}^{ - 1} ) + ( {8}^{ - 1} ) \times ( \frac{4}{9} )^{ - 1}$
2. $( \frac{1}{4} ) + ( \frac{1}{8} ) \times \frac{9}{4}$
3. $\frac{8}{32} + \frac{9}{32}$
4. $\frac{17}{32}$