Question

${4}^{2} - 2( {a}^{2} + {b}^{2} )x + {a}^{2} {b}^{2}$
solve for x

Answer 1

heya..!!!!!


4x² - 2(a² + b²)x + a²b² = 0

=> 4x² - 2a²x - 2b²x + a²b² = 0

=> 2x(2x - a²) - b²( 2x - a²) = 0

=> (2x - b²)(2x - a²) = 0

=> x = b²/2 AND x = a²/z