Question

$4 ^{2} + 4 ^{n + 2} = a \times 4^{n}$
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Answer 1

Answer:

${4}^{2} + {4}^{ n+ 2} = a \times {4}^{n} \\ \\ \frac{ {4}^{2} + {4}^{n + 2} }{ {4}^{n} } = a \\ \\ {4}^{2 - n} + {4}^{2} = a \\ \\ {4}^{2 - n} = a - 16$