Math, asked by thakursavita568, 7 months ago


 {4}^{2}  +  {5}^{2}  +  {a}^{2}  =  {21}^{2} find \: the \: value \: of \: a

Answers

Answered by wwwjyoti1590com
1

Answer:

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Answered by Anonymous
2

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\sf\implies {4}^{2} +  {5}^{2}  +  {a}^{2}  =  {21}^{2}

\sf\implies16 + 25 +  {a}^{2}  = 441

\sf\implies41 +  {a}^{2}  = 441

\sf\implies {a}^{2}  = 441 - 41

\sf\implies {a}^{2}  = 400

\sf\implies \: a =  \sqrt{400}

\sf\implies \: a = 20

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