Question

${4}^{2} + {5}^{2} + {a}^{2} = {21}^{2} find \: the \: value \: of \: a$
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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$\sf\implies {4}^{2} + {5}^{2} + {a}^{2} = {21}^{2}$

$\sf\implies16 + 25 + {a}^{2} = 441$

$\sf\implies41 + {a}^{2} = 441$

$\sf\implies {a}^{2} = 441 - 41$

$\sf\implies {a}^{2} = 400$

$\sf\implies \: a = \sqrt{400}$

$\sf\implies \: a = 20$

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