Question

$-4/27xy^{2} (9/2x^{2} yz3/4xyz^{2} )$ Pls step by step

Answer 1

Question :-

$(\frac{-4}{27})xyz ((\frac{9}{2})x^{2}yz-(\frac{3}{4})xyz^{2})$  

Solution :-

Let p, q and r be three monomials.

Then, by distributive law of multiplication over subtraction, we have:

P × (q – r) = (p × q) – (p × r)

Now,

= ((-4/27)xyz × (9/2)x2yz) – ((-4/27)xyz × (-3/4)xyz2)

= ((-4×9)/ (27×2))x3y2z2 + ((-4×-3)/(27×4))x2y2z3 … [∵ $a^{m} X a^{n} = a^{m+n}$]

= ((-2×1)/ (3×1))x3y2z2 + ((-1×-1)/(9×1))x2y2z3  

= (-2/3)x3y2z2 + (1/9)x2y2z3

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Answer 2

:(3m-4n)(2m-3n)6m^2-9mn-8mn+12n^26m^2-mn+12n^2 .......