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4(2x+1) = 3(x-1)+7.
Opening brackets:
8x+4 = 3x-3+7.
8x+4 = 3x+4.
Subtracting 4 on both the sides:
8x+4-4 = 3x+4-4.
8x = 3x.
Sending 3x to LHS:
8x-3x = 0.
5x = 0.
Dividing both the sides by 5:
5x/5 = 0/5.
x = 0.
Therefore, we found out that the value of x is 0.
Checking by substituting x with 0:
4[2(0)+1] = 3[0-1]+7
4[1] = 3(-1)+7
4=-3+7.
4=4.
Therefore, as LHS = RHS, we can say that x=0 is the solution of the equation 4(2x+1) = 3(x-1)+7.
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hey!!!!
4(2x+1)=3(x-1)+7
=8x+4=3x-3+21
= 8x-3x= 21-3-4
= 5x=21-7
=5x=14
x=14/5
x= 2 4/5
Hope it helps!!!...
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4(2x+1)=3(x-1)+7
=8x+4=3x-3+21
= 8x-3x= 21-3-4
= 5x=21-7
=5x=14
x=14/5
x= 2 4/5
Hope it helps!!!...
Please nark it as brainliest...
And don't forget to follow me...
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