Question

${4}^{3} + \frac{1 {}^{} }{4 {}^{3} }$
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Answer 1

${4}^{3} \\ 64 \\ 64 + \frac{1}{64} \\ \frac{4096 + 1}{64} \\ \frac{4097}{64}$

hope it helps

Answer 2

Answer:

plz follow me

Step-by-step explanation:

4^6+1/4^3

4096+1/64

4097/64