Question

$(4 + 38x + 7 {x}^{2} + 42 {x}^{2}) + (22 + 29x + 6 {x}^{2}39x)$
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Answer 1

Answer:

$(4 + 38x + 7 {x}^{2} + 42 {x}^{2} ) + (22 + 29x + 6 {x}^{2} 39x)$

$4+38x+7x^{2}+42x^{2}+22+29x+6x^{3}\times 39$

$4+38x+49x^{2}+22+29x+6x^{3}\times 39$

$26+38x+49x^{2}+29x+6x^{3}\times 39$

$26+67x+49x^{2}+6x^{3}\times 39$

$26+67x+49x^{2}+234x^{3}$

Rearrange according to power.

$234^{3}+49x^{2}+69x+26$

Answer 2

Answer:

Step-by-step explanation: