Question

$4 {(3x - 2y)} ^{2} - 8x + 12y - 3$
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Answer 1

Step-by-step explanation:

$4 {(3x - 2y)}^{2} - 8x + 12y - 3 = 0 \\ 4(9 {x}^{2} + 4 {y}^{2} - 12xy) + 12y - 3 = 0 \\ 36 {x}^{2} + 16 {x}^{2} - 48xy + 12y - 3 = 0$