Question

$4 + 5 - 7 + 8 \times 5 - 12 \times \frac{8}{2} + 6 - 3 + \frac{20}{2}$
solve by board mass​

Answer 1

Answer :-

BODMAS :-

• B - Brackets ( ) { } [ ]
• O - Of
• D - Division
• M - Multiplication
• A - Addition
• S - Subtraction

$\implies\sf 4 + 5 - 7 + 8 \times 5 - 12 \times \dfrac{8}{2} + 6 - 3 + \dfrac{20}{2}$

• $\sf \dfrac{8}{2} = 4$
• $\sf \dfrac{20}{2} = 10$

$\implies\sf 4 + 5 - 7 + 8 \times 5 - 12 \times \bold 4 + 6 - 3 + 10$

• $\sf 8 \times 5 = 40$
• $\sf 12 \times 4 = 48$

$\implies\sf 4 + 5 - 7 + \bold{40} - \bold{48} + 6 - 3 + 10$

$\implies\sf 4 + 5 + 40 + 10 + 6 - 7 - 48 - 3$

$\implies\sf 9 + 40 + 10 + 6 - 7 - 48 - 3$

$\implies\sf 49 + 10 + 6 - 7 - 48 - 3$

$\implies\sf 59 + 6 - 7 - 48 - 3$

$\implies\sf 65 - 7 - 48 - 3$

$\implies\sf 58 - 48 - 3$

$\implies\sf 10 - 3$

$\implies\sf 7$

Answer 2

$\huge{\underline{\underline{\mathrm{\red{AnswEr}}}}}$

BODMAS :-

B - Brackets ( ) { } [ ]

O - Of

D - Division

M - Multiplication

A - Addition

S - Subtraction

$\implies\sf 4 + 5 - 7 + 8 \times 5 - 12 \times \dfrac{8}{2} + 6 - 3 + \dfrac{20}{2}$

$\sf \dfrac{8}{2} = 4$

$\sf \dfrac{20}{2} = 10$

$\implies\sf 4 + 5 - 7 + 8 \times 5 - 12 \times \bold 4 + 6 - 3 + 10$

$\sf 8 \times 5 = 40$

$\sf 12 \times 4 = 48$

$\implies\sf 4 + 5 - 7 + \bold{40} - \bold{48} + 6 - 3 + 10$

$\implies\sf 4 + 5 + 40 + 10 + 6 - 7 - 48 - 3$

$\implies\sf 9 + 40 + 10 + 6 - 7 - 48 - 3$

$\implies\sf 49 + 10 + 6 - 7 - 48 - 3$

$\implies\sf 59 + 6 - 7 - 48 - 3$

$\implies\sf 65 - 7 - 48 - 3$

$\implies\sf 58 - 48 - 3$

$\implies\sf 10 - 3$

$\implies\sf 7$

${\huge{\underline{\small{\mathbb{\pink{HOPE \ THIS \ HELPED \ UH♡}}}}}}$