Question

$4 - \frac{2(z - 4)}{3} = \frac{1}{2} (2z+ 5$
plz answer this ​

Answer 1

Given 4 - (2(z - 4))/ 2 = 1/2(2z + 5)

Now by taking L.C.M of 1 nad 2 is 3

12 - 2 (z - 4)/3 = (2z + 5)/2

By cross multiplication we get

2(12 - 2z + 8) = 3(2z + 5)

40 - 4z = 6z + 15

-10z = -25

z = 25/10 = 5/2

Answer 2

Step-by-step explanation:

$4 - \frac{2(z - 4)}{3} = \frac{1}{2} (2z + 5)$

$4 - \frac{2z - 8}{3} = \frac{2z + 5}{2}$

$4 - \frac{2z - 8}{3} - \frac{2z + 5}{2} =$

$\frac{24 - 2(2z - 8) - 3(2z + 5)}{6} </p><p>=0$

$24 - 4z + 16 - 6z - 15 = \: \\ \\ 024−4z+16−6z−15=0$

$- 10z + 25 = 0−10z+25=0$

$- 10z = - 25−10z=−25$

$z = \frac{25}{10}$

$z = 2.5z=2.5$