Question

$4 + \sqrt{3 ) \div 4 - \sqrt{3} = x + y \sqrt{3}$
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Answer 1

Step-by-step explanation:

$((4 + \sqrt{3})\div (4 - \sqrt{3})) \times((4 + \sqrt{3})\div (4 + \sqrt{3})) = x + y \sqrt{3}$

$= > ((4 + \sqrt{3})^{2}\div ( {4}^{2} - { (\sqrt{3} }^{2} ))$

$= > (16 + 3 + 8 \sqrt{3} ) \div (16 - 3) \\ = > (21 + 8 \sqrt{3} ) \div 13$

Here, x= 21/13 , y = 8/13