Math, asked by himanshunayak69, 9 months ago


4 \sqrt{3 \sqrt{2 {}^{2} } }

Answers

Answered by Anonymous
2

Answer:

4 \sqrt{3 \sqrt{2 {}^{2} } }  \\  \\  \\  =  > 4 \sqrt{3 \times 2}  \\  \\  \\  =  >  4\sqrt{6}

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Answered by sabyasachi2005
0

Answer:

4\sqrt{6}

Step-by-step explanation:

first root of sqrt{2{}^{2}} is 2

2*3=6

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